What difference between $* and $@
All arguments are double-quoted when they are marked with $* or $@, respectively.
What is $* and $@ in Linux
Basically, $# is a number of arguments given when your script was executed, and $* is a string containing all arguments. For instance, $1 is the first argument, and so on. “$@” stores all the arguments that were entered on the command line, individually quoted (“$1” “$2”).
What does $* mean in Bash
All arguments are listed in a space-separated string, so if $1 is “hello” and $2 is “world,” then $* is “hello world.”
What is the difference between $* and $@ When quoted
When used as command arguments, $* is equivalent to $1d$2d'', where d is the first character of the IFS variable, while $@ is equivalent to $1 $2. When used without quotation marks, as a parameter assignment value, or as a file name, the meaning of $* and $@ is identical.
What is the use of $* in shell scripting
It denotes all of the word-by-word arguments passed to the script or function. 13 September 2012
What is difference between $$ and $!
18: Whats the difference between $$ and $!? $$ displays the process id of the recently-gone-into-the-background process, whereas $! displays the process id of the currently-executing process.
What is $* in Makefile
If you were to run make foobar.xyz, this rule would run make foobar clean: it would run a sub-make, build the foobar target, then build the clean target. Here, $* is an automatic variable that will expand to the stem of the target (the text matching the% in the pattern).
What is $# in shell
This is because, while a shell function is running, the positional parameters are temporarily replaced with the arguments to the function, allowing functions to accept and use their own positional parameters. $# is the number of positional parameters passed to the script, shell, or shell function.
What does $@ mean
Place variables in quotes if the values may contain spaces. $@ refers to all of a shell scripts command-line arguments. $1, $2, etc., refers to the first command-line argument, the second command-line argument, etc.
What does $? Mean in Linux
echo $? – Returns the EXIT STATUS of the most recently executed command. This EXIT STATUS is likely to be a number, with a value of ZERO denoting success and any value other than ZERO denoting failure.
What is difference between && and in Linux
While ; always executes the second command, && allows for conditional execution.
What is the difference between * and &
The * is a unary operator that returns the value of the object pointed by a pointer variable. It is also known as the value of the operator. The & is a unary operator in C that returns the memory address of the passed operand.
What does * and & mean in C++
Simply put, & means the address-of, * means the dereference of a pointer variable, which means to get the value of that pointer variable. You will see that in placeholders for functions to modify the parameter variable as in C, parameter variables are passed by value, using the ampersand means to pass by reference.
What is the difference between comments and /* Comments
The double-slash comments (//) expire at the end of the line, whereas the slash-star (/*) style comments remain in effect until a closing comment mark (*/).
IS & the same as * in C
& can be either the address-of operator or (in C) part of the reference declaration syntax, while * can either be the dereference operator or a component of the pointer declaration syntax.
What is the meaning of * in C
tmp = *str; instructs the computer to fill the character tmp with the first character from the string array pointed to by the pointer str. The asterisk designates a pointer char tmp, which is a character char * str.
What is &X in C
There is no padding in arrays, so &x is a pointer to the first element of the x array and is of type int *, whereas &x is a pointer to the x array, and both have the same value: (int *) &x == x /* in a value context the expression evaluates to 1 */
What is && operator in C
The && (logical AND) operator determines whether both operands are true. If both operands have nonzero values, the result is 1; otherwise, it is 0. The result is an int, and both operands must be of an arithmetic or pointer type.